Given an array and a value, remove all instances of that value in place and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
Example:
Given input array nums = [3,2,2,3], val = 3
Your function should return length = 2, with the first two elements of nums being 2.
给定一个数组，不重新非配空间，去除和给定值相同的值，返回数组新的长度
C代码
#include <assert.h>
int removeElement(int *nums, int numsSize, int val) {
int i = 0;
int begin = 0;
for(i = 0; i < numsSize; i++) {
if(*(nums+i) != val)
*(nums+begin++) = *(nums+i);
}
return begin;
}
int main() {
int nums[4] = {3,2,2,3};
int val = 3;
assert(removeElement(nums, 4, val) == 2);
assert(nums[0] == 2);
return 0;
}
