Given a time represented in the format "HH:MM", form the next closest time by reusing the current digits. There is no limit on how many times a digit can be reused.
You may assume the given input string is always valid. For example, "01:34", "12:09" are all valid. "1:34", "12:9" are all invalid.
Example 1:
Input: "19:34"
Output: "19:39"
Explanation: The next closest time choosing from
digits 1, 9, 3, 4, is 19:39, which occurs 5 minutes later.
It is not 19:33, because this occurs 23 hours and 59 minutes later.
Example 2:
Input: "23:59"
Output: "22:22"
Explanation: The next closest time choosing from
digits 2, 3, 5, 9, is 22:22.
It may be assumed that the returned time is next day's time
since it is smaller than the input time numerically.
class Solution {
public String nextClosestTime(String time) {
String h = time.substring(0,2);
String m = time.substring(3);
int timeValue = getTimeValue(h, m);
char[] digits = (h+m).toCharArray();
String result = "";
int min_diff = Integer.MAX_VALUE;
String min_result = "";
int min = Integer.MAX_VALUE;
for(char a:digits){
for(char b:digits){
for(char c:digits){
for(char d:digits){
String newh = new String(new char[]{a,b});
String newm = new String(new char[]{c,d});
if(isValidTime(newh, newm)){
int diff = getTimeValue(newh, newm)-timeValue;
if(diff>0 && diff<min_diff){
min_diff = diff;
result = newh+":"+newm;
}
if(getTimeValue(newh, newm)<min){
min = getTimeValue(newh, newm);
min_result = newh+":"+newm;
}
}
}
}
}
}
if(min_diff<1500) return result;
else return min_result;
}
public boolean isValidTime(String h, String m){
int hvalue = Integer.valueOf(h);
int mvalue = Integer.valueOf(m);
if(hvalue>23 || hvalue<0 || mvalue<0 || mvalue>59) return false;
return true;
}
public int getTimeValue(String h, String m){
int hvalue = Integer.valueOf(h);
int mvalue = Integer.valueOf(m);
return hvalue*60 + mvalue;
}
}