题目链接
Reverse digits of an integer.
Example1: x = 123, return 321Example2: x = -123, return -321
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**Note:
**The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows.
解题思路
TODO（稍后补充）
解题代码
class Solution {
public:
int reverse(signed int x) {
vector<int> tmp(32,-1);
long input=0 ,flag = 0, index=0;
if (x > 0) {
input = x;
}else {
input = 0-x;
flag = 1;
if (x == min) input = max+1;
//cout<<"gergerg: "<<input<<endl;
}
while (input/10 != 0) {
int residual = input%10;
input = input/10;
tmp[index++] = residual;
}
tmp[index] = input;
// if reversed integer overflows, return 0
long output = 0;
index = 0;
while (tmp[index] != -1) {
output = output*10 + tmp[index++];
}
//cout <<output<<endl;
if ((flag == 1 && (0 - output) < min) or (flag == 0 && output > max)) {
return 0;
}
return flag == 1 ? 0 - output : output;
}
private:
long max = 2147483647;
long min = -2147483648;
};
