又不知道怎么开头,还是直接上需求吧。简单粗暴,就是按照UI的图做就是咯~~~
拿到这个需求的时候,问到底什么情况是低什么是中什么是高,结果告诉我自己解决,我特么不是设计啊,我怎么知道,然后自己默默的去网上搜了了一堆判断,然后来解决吧。
#pragma mark - 判断密码强度函数
/*
声明:包含大写/小写/数字/特殊字符
两种以下密码强度低
两种密码强度中
大于两种密码强度高
密码强度标准根据需要随时调整
*/
//判断是否包含
+ (BOOL) judgeRange:(NSArray*) _termArray Password:(NSString*) _password
{
NSRange range;
BOOL result =NO;
for(int i=0; i<[_termArray count]; i++)
{
range = [_password rangeOfString:[_termArray objectAtIndex:i]];
if(range.location != NSNotFound)
{
result =YES;
}
}
return result;
}
//条件
+ (NSString*) judgePasswordStrength:(NSString*) _password
{
NSMutableArray* resultArray = [[NSMutableArray alloc] init];
NSArray* termArray1 = [[NSArray alloc] initWithObjects:@"a", @"b", @"c", @"d", @"e", @"f", @"g", @"h", @"i", @"j", @"k", @"l", @"m", @"n", @"o", @"p", @"q", @"r", @"s", @"t", @"u", @"v", @"w", @"x", @"y", @"z", nil];
NSArray* termArray2 = [[NSArray alloc] initWithObjects:@"1", @"2", @"3", @"4", @"5", @"6", @"7", @"8", @"9", @"0", nil];
NSArray* termArray3 = [[NSArray alloc] initWithObjects:@"A", @"B", @"C", @"D", @"E", @"F", @"G", @"H", @"I", @"J", @"K", @"L", @"M", @"N", @"O", @"P", @"Q", @"R", @"S", @"T", @"U", @"V", @"W", @"X", @"Y", @"Z", nil];
NSArray* termArray4 = [[NSArray alloc] initWithObjects:@"~",@"`",@"@",@"#",@"$",@"%",@"^",@"&",@"*",@"(",@")",@"-",@"_",@"+",@"=",@"{",@"}",@"[",@"]",@"|",@":",@";",@"“",@"'",@"‘",@"<",@",",@".",@">",@"?",@"/",@"、", nil];
NSString* result1 = [NSString stringWithFormat:@"%d",[self judgeRange:termArray1 Password:_password]];
NSString* result2 = [NSString stringWithFormat:@"%d",[self judgeRange:termArray2 Password:_password]];
NSString* result3 = [NSString stringWithFormat:@"%d",[self judgeRange:termArray3 Password:_password]];
NSString* result4 = [NSString stringWithFormat:@"%d",[self judgeRange:termArray4 Password:_password]];
[resultArray addObject:[NSString stringWithFormat:@"%@",result1]];
[resultArray addObject:[NSString stringWithFormat:@"%@",result2]];
[resultArray addObject:[NSString stringWithFormat:@"%@",result3]];
[resultArray addObject:[NSString stringWithFormat:@"%@",result4]];
int intResult=0;
for (int j=0; j<[resultArray count]; j++)
{
if ([[resultArray objectAtIndex:j] isEqualToString:@"1"])
{
intResult++;
}
}
NSString* resultString = [[NSString alloc] init];
if (intResult < 2)
{
resultString = @"0";
}
else if (intResult == 2&&[_password length]>=6)
{
resultString = @"1";
}
if (intResult > 2&&[_password length]>=6)
{
resultString = @"2";
}
return resultString;
}
有了这个好像已经成功了一半,但是怎么让它显示呢,那么
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {
NSString *resultString = [[NSString alloc]init];
if ([string isEqualToString:@""]) { //按了删除键
resultString = [textField.text substringToIndex:textField.text.length - 1];
} else {
resultString = [NSString stringWithFormat:@"%@%@",textField.text,string];
}
NSInteger result = [[NSString judgePasswordStrength:resultString] integerValue];
switch (result) {
case 0:
_lowLabel.textColor = xxx;
_middleLabel.textColor = xxx;
_highLabel.textColor = xxx;
break;
case 1:
_middleLabel.textColor = xxx;
_lowLabel.textColor = xxx;
_highLabel.textColor = xxx;
break;
case 2:
_highLabel.textColor = xxx;
_lowLabel.textColor = xxx;
_middleLabel.textColor = xxx;
break;
default:
break;
}
return YES;
}
代码很简单没什么解释的,嘻嘻嘻,有需要的可以参考参考,睡觉了。