如果将一个浮点数转化为整数的话，Java会如何处理呢
public class T {
public static void main(String [] args){
float fa = 0.4f;
float fb = 0.7f;
double da = 0.4;
double db = 0.7;
System.out.println("Float to int below:"+(int)fa);
System.out.println("Float to int above:"+(int)fb);
System.out.println("Double to int below:"+(int)da);
System.out.println("Double to int above:"+(int)db);
}
}
输出结果
Float to int below:0
Float to int above:0
Double to int below:0
Double to int above:0
这里可以看出不论是float还是double，在转化为int时会被截尾（小数点后面的都被截断），那么要怎么才能得到四舍五入的结果呢？这就得用到Math.round()方法了
public class T {
public static void main(String [] args){
float fa = 0.4f;
float fb = 0.7f;
double da = 0.4;
double db = 0.7;
System.out.println("Float to int below:"+Math.round(fa));
System.out.println("Float to int above:"+Math.round(fb));
System.out.println("Double to int below:"+Math.round(da));
System.out.println("Double to int above:"+Math.round(db));
}
}
输出结果
Float to int below:0
Float to int above:1
Double to int below:0
Double to int above:1