今天和同事讨论，头条面试的算法题，他说问了一个金额大小写转换的，即1024 转成壹千零贰拾肆圆整，然后自己尝试一下了（不考虑小数，金额数字小数点只能到两位了）
具体思路如下：逐个读取每个数字，然后对应取中文数字，并加上中文单位，最后把一些需要处理的描述，比如零零，换成零，把零万，换成零等。
具体如下：
package main
import (
"fmt"
"strings"
)
func transfer(num int) string{
chineseMap:=[]string{"圆整","十", "百", "千", "万", "十", "百", "千", "亿", "十", "百", "千"}
chineseNum:=[]string{"零", "壹", "贰","叁","肆","伍","陆","柒","捌","玖"}
listNum := []int{}
for ;num >0;num = num/10{
listNum= append(listNum, num%10)
}
n :=len(listNum)
chinese :=""
//注意这里是倒序的
for i:=n-1; i>=0 ;i-- {
chinese = fmt.Sprintf("%s%s%s", chinese, chineseNum[listNum[i]], chineseMap[i])
}
//注意替换顺序
for {
copychinese:=chinese
copychinese = strings.Replace(copychinese, "零万", "万", 1)
copychinese = strings.Replace(copychinese, "零亿", "亿", 1)
copychinese = strings.Replace(copychinese, "零十", "零", 1)
copychinese = strings.Replace(copychinese, "零百", "零", 1)
copychinese = strings.Replace(copychinese, "零千", "零", 1)
copychinese = strings.Replace(copychinese, "零零", "零", 1)
copychinese = strings.Replace(copychinese, "零圆", "圆", 1)
if copychinese == chinese {
break
}else {
chinese= copychinese
}
}
return chinese
}
func main() {
fmt.Println(1024, transfer(1024))
fmt.Println(1004, transfer(1004))
fmt.Println(101004, transfer(101024))
fmt.Println(1010004, transfer(1010004))
fmt.Println(3000010004, transfer(3000010004))
}
测试一下
1024 壹千零贰十肆圆整
1004 壹千零肆圆整
101004 壹十万壹千零贰十肆圆整
1010004 壹百零壹万零肆圆整
3000000 叁百万圆整
3000010004 叁十亿零壹万零肆圆整
