基本写法，输出数据数据都被转换成double：

Gson gson = new GsonBuilder().disableHtmlEscaping().create();
return gson.fromJson(psiFile.getText(), TestDataModel.class);

解决方案：

Gson gson = new GsonBuilder()
                .registerTypeAdapter(Map.class, new JsonDeserializer<Map>() {
                    @Override
                    public Map deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
                        LinkedTreeMap<String,Object> m  = new LinkedTreeMap<String, Object>();
                        JsonObject jo = json.getAsJsonObject();
                        for (Map.Entry<String, JsonElement> mx : jo.entrySet()){
                            String key = mx.getKey();
                            JsonElement v = mx.getValue();
                            if(v.isJsonArray()){
                                m.put(key, context.deserialize(v, List.class));
                            }else if(v.isJsonPrimitive()){
                                Object value = v.getAsString();
                                try {
                                    Object numValue = NumberFormat.getInstance().parse((String)value);
                                    if (numValue != null && numValue.toString().equals(value)) {
                                        value = numValue;
                                    }
                                } catch (Exception e) {
                                }
                                m.put(key, value);
                            }else if(v.isJsonObject()){
                                m.put(key,context.deserialize(v, Map.class));
                            }
                        }
                        return m;
                    }
                })
                .create();
return gson.fromJson(psiFile.getText(), TestDataModel.class);

原文地址：https://stackoverflow.com/questions/17090589/gson-deserialize-integers-as-integers-and-not-as-doubles/59058304#59058304?newreg=4e453258365f433d9144b7dd62dcef95